16x^2+40+25=3x+17

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Solution for 16x^2+40+25=3x+17 equation: 



16x^2+40+25=3x+17

We move all terms to the left:

16x^2+40+25-(3x+17)=0

We add all the numbers together, and all the variables

16x^2-(3x+17)+65=0

We get rid of parentheses

16x^2-3x-17+65=0

We add all the numbers together, and all the variables

16x^2-3x+48=0

a = 16; b = -3; c = +48;
Δ = b2-4ac
Δ = -32-4·16·48
Δ = -3063
Delta is less than zero, so there is no solution for the equation

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